From: brabuhr@...
Date: 2008-08-19T03:03:23+09:00
Subject: Re: Need ruby code to get a latest file from a Directory

On Mon, Aug 18, 2008 at 1:23 PM, Rajeswar reddy Gaulla
<rajeswarr@ivycomptech.com> wrote:
> I am having log files with time stamp in a log directory, how to open a
> latest log file and read it?.
>
> Eg:
> directory name log/
> files
>     log/log20080812152634Lbuild.34.xml
>     log/log20080812122634Lbuild.34.xml
>     log/log20080812102634Lbuild.34.xml
>     log/log20080811142634Lbuild.34.xml
>     log/log20080811122634Lbuild.34.xml
>
> If anybody know the solution, please let me know.

Maybe something like:

newest_file = Dir.entries(Dir::pwd).sort_by{|e|
  # assuming that the files are always log + TIMESTAMP + L:
  scan(/log\d{14}L/)[0]
}.last

File.open(newest_file, "r") do |f|
  #...
end

?