From: "Thomas Bl." <tpreal@...>
Date: 2008-08-16T23:09:39+09:00
Subject: Re: Stumped on simple wildcard

>   domain = ENV['HTTP_HOST']
>   if domain == '*domain1.com'; printf "<h2>Welcome to Domain 1</h2>"
>   elsif domain == '?domain2.com'; printf "<h2>Welcome to Domain 2</h2>"
>   elsif domain == 'domain3.com'; printf "<h2>Welcome to Domain 3</h2>"
>   elsif domain == 'domain4.com'; printf "<h2>Welcome to Domain 4</h2>"
>   elsif domain == 'domain5.com'; printf "<h2>Welcome to Domain 5</h2>"
>   end

Hello. When you compare two strings using ==, it is the exact match and 
there are no wildcards in this kind of comparison. Use Regexen for your 
task.

Try this:

if mat=domain.match(/domain([0-9])\.com$/i)
  dm=mat[1].to_i
  if (1..5).include?(dm)
    printf "<h2>Welcome to Domain #{dm}</h2>"
  else
    # bad domain number
  end
else
  # not matching the pattern
end

If you have domains with more digits (10, 11, ...), change to ([0-9]+) 
in the Regex. Note the dot before com is escaped. The $ at the end means 
that the string must end at com (without it, www.domain4.com.ru would 
qualify also). The /i at the end of the pattern makes it case 
insensitive. mat[1] reads the first parenthesised group from the Regexp, 
which is the domain number in our case.

Hope that helped.
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