From: Gregory Brown <gregory.t.brown@...>
Date: 2008-08-01T06:08:39+09:00
Subject: Re: super with block

On Thu, Jul 31, 2008 at 4:51 PM, Lou Zell <lzell11@gmail.com> wrote:
> Lou Zell wrote:
>> Mikael, I can deal with that, I'll swap out the $'s with block params.
>> Thanks for the workaround!
>>
>> Lou
>
> Actually, this did not work the way I expected.  It is fine for a case
> like this:
> str = "match1"
> gsub!(/(match1)/) {|m| m}
>
> But not this:
> str = "match1match2"
> gsub!(/(match1)(match2)/) {|m1,m2| m1 + m2}
>
> Where I am really looking for:
> str = "match1match2"
> gsub!(/(match1)(match2)/) { $1 + $2}
>
>
> So let me ask this instead:  How do I pass a block from one method to
> another without invoking the block?

I forgot to answer this before:

>> class String
>>   def nsub!(*args,&block)
>>     gsub!(args[0],&block)
>>   end
>> end

But unfortunately, this does not fix your problem:

>> str = "match1match2"
=> "match1match2"
>> str.nsub!(/(match1)(match2)/) { |m| $1 + "---" + $2 }
NoMethodError: undefined method `+' for nil:NilClass