From: CompGeek78 <keven.denen@...>
Date: 2008-08-01T03:09:15+09:00
Subject: Question on do block

While going through some practice code from a book, I ran into an odd
issue with this do block.

The book put the code this way and it worked fine.

def mtdarry
  10.times do |num|
    square = num * num
    return num, square if num > 7
  end
end

num, square = mtdarry
puts num
puts square

This returns 8 and 64, which makes sense.

The problem I ran into is in changing the > to a =.

def mtdarry
  10.times do |num|
    square = num * num
    return num, square if num = 7
  end
end

num, square = mtdarry
puts num
puts square

At this point, it outputs 7 and 0. Why does it not calculate the value
of square properly?