From: Robert Dober <robert.dober@...>
Date: 2008-08-01T02:37:51+09:00
Subject: Re: super with block

On Thu, Jul 31, 2008 at 7:10 PM, Lou Zell <lzell11@gmail.com> wrote:
>> Hi,
>>
>> This worked for me:
>>
>> irb(main):023:0> class NString < String
>> irb(main):024:1>  def gsub!(*args, &blk)
>> irb(main):025:2>  super(*args, &blk)
>> irb(main):026:2> end
>> irb(main):027:1> end
>> => nil
>> irb(main):028:0> s = NString.new("hi")
>> => "hi"
>> irb(main):029:0>  s.gsub!(/(hi)/){$1}
>> => "hi"
>>
>> Hope this helps,
>>
>> Jesus.
>
>
> Hi Jesus, thank you for your response.  Unfortunately, I could not
> replicate your results:
>
>
>>> class NString < String
>>> def gsub!(*args, &blk)
>>> super(*args, &blk)
>>> end
>>> end
> => nil
your problem has nothing to do with passing the block along in gsub!
>>> s = NString.new("hi")
guess what s is here?
If you guessed "", you guessed correctly
> => "hi"
>>> s.gsub!(/(hi)/){$1}
> => ""
normal given that s was ""

Probably subclassing is not what you want, but it can be accomplished of course

>
>
> Perhaps it is my version of ruby?
> ~$ ruby -v
> ruby 1.8.6 (2008-03-03 patchlevel 114) [universal-darwin9.0]
>
>
> Lou
> --
> Posted via http://www.ruby-forum.com/.
>
>

Here is the final solution
class NString < String
 def initialize str
    replace str
 end
 def gsub! *args
   super( *args, &Proc::new ) # that is just to show you yet another
way to do this but passing &blk is better
end
end

n = Nstring::new( "123")
p n
p n.gsub!(/.../){ |m| m.reverse } # $1 is not set as somebody did
point out already

HTH
Robert


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