From: jazzez ravi <jazzezravi@...>
Date: 2008-07-31T20:40:58+09:00
Subject: Re: Help me with this Numerology code please...

Web Reservoir wrote:
> Hi,
> 
> I am planning to implement a Numerology code like this.
> 
> Every alphabet in Numerology is given a number like this...
> 
> --------------------------------------------------------------
> 1     2     3     4      5      6     7     8      9
> 
> A     B     C     D      E      F     G     H      I
> 
> J     K     L     M      N      O     P     Q      R
> 
> S     T     U     V      W      X     Y      Z
> ----------------------------------------------------------
> 
> Or you can even say that
> 
> 1 = A, J, S
> 2 = B, K, T
> 3 = C, L, U
> 4 = D, M, V
> 5 = E, N, W
> 6 = F, O, X
> 7 = G, P, Y
> 8 = H, Q, Z
> 9 = I, R
> 
> Now when you type RUBY you should get the total as 9+3+2+7 = (21) 2+1 =
> 3
> where R = 9, U = 3, B = 2 and y = 7 ( as shown above )
> 
> Have a look at the working example here...
> 
> http://www.numerology.googlepages.com/Numerology_nameNumberdetails.htm
> 
> and
> 
> http://www.numerology.googlepages.com/Numerology_nameNumber.htm
> 
> I would like to code this in Ruby. Pl. help me with this code.
> 

Hi Reservoir,

i think this code satisfy your need...


class Reservoir
def main

   a="mahalingam" # your name

   val={"a"=>1,"j"=>1,"s"=>1,
        "b"=>2,"k"=>2,"t"=>2,
        "c"=>3,"l"=>3,"u"=>3,
        "d"=>4,"m"=>4,"v"=>4,
        "e"=>5,"n"=>5,"w"=>5,
        "f"=>6,"o"=>6,"x"=>6,
        "g"=>7,"p"=>7,"y"=>7,
        "h"=>8,"q"=>8,"z"=>8,
        "i"=>9,"r"=>9}


   num=[]
   i=0
   while i < a.length do
     num << val[a[i,1]]
     i+=1
   end
   mind(num)
end


def mind(num)
  no=[]
  no=num
   j=0

   final=0
   while j < no.length
     final +=num[j].to_i
      j+=1
    end
    output= final.to_s
    if output.length !=1
      output2=output.split(//)
      mind(output2)
      else
        puts final
    end
 end
end

res=Reservoir.new
res.main


Regards,
P.Raveendran
RF,Chennai
http://raveendran.wordpress.com

-- 
Posted via http://www.ruby-forum.com/.