From: Ben Brightwell <neogia4@...>
Date: 2008-07-29T14:03:26+09:00
Subject: Re: Another Deaf Grandma Topic, different issue

Phee Luche wrote:
> I'm trying to learn using a tut, and I'm getting stuck on one of the
> exercises. Google is giving me squat.
> 
> It's about Flow Control, specifically while and if-then. I understand it
> totally, but I need, well, it's hard to explain.
> 
> I've successfully finished this:
> 
> Write a Deaf Grandma program. Whatever you say to grandma (whatever you
> type in), she should respond with HUH?! SPEAK UP, SONNY!, unless you
> shout it (type in all capitals). If you shout, she can hear you (or at
> least she thinks so) and yells back, NO, NOT SINCE 1938! To make your
> program really believable, have grandma shout a different year each
> time; maybe any year at random between 1930 and 1950. (This part is
> optional, and would be much easier if you read the section on Ruby's
> random number generator at the end of the methods chapter.) You can't
> stop talking to grandma until you shout BYE.
> Hint: Don't forget about chomp! 'BYE'with an Enter is not the same as
> 'BYE' without one!
> Hint 2: Try to think about what parts of your program should happen over
> and over again. All of those should be in your while loop.[/spoiler]
> 
> But now I need to do a bit more, and I can't figure out how to do this:
> 
> Extend your Deaf Grandma program: What if grandma doesn't want you to
> leave? When you shout BYE, she could pretend not to hear you. Change
> your previous program so that you have to shout BYE three times in a
> row. Make sure to test your program: if you shout BYE three times, but
> not in a row, you should still be talking to grandma.
> 
> Oh, and here's my code:
> 
> puts 'it\'s yer ol\' gramma hobblin\' over! What do you say?'
> you=gets.chomp
> 
> 
>  while you!='BYE'
>       if you!=you.upcase.chomp
>       then
>       puts 'HUH?! SPEAK UP, SONNY!'
>       you=gets.chomp
>       else
>         if you==you.upcase.chomp
>           then
>           puts 'NO, NOT SINCE 19'+(rand(21)+30).to_s+'!'
>           you=gets.chomp
>         end
>       end
>  end

Phee, in the expression for your while loop ( you != 'BYE' ), your 
program will exit after precisely 1 'BYE' entered by the user. This 
should be the first place you look, since you don't want your program to 
exit until there are a total of three 'BYE' entries in a row.

My first thought would be to keep a count of how many times the user has 
input 'BYE' and check that against 3 ( while bye_count != 3 ).

Hope that helps.
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