From: "Albert L. Wagner" <alwagner@...>
Date: 2002-01-12T00:57:11+09:00
Subject: Re: "each" in iterator: confusion

Ah, hah!  Thank you both.  It seems so obvious when you point it
out, but if I didn't risk feeling foolish I never would have seen
it.  Thanks again.

"Albert L. Wagner" wrote:
> 
> I do not understand why this code runs forever.  Is it because
> the yield is taken to be a second yield in the super class
> "each"?  Is there a way to do such nested iterators?
> 
> class MyHash < Hash
>     def each(&block)
>         super.each do | k, v |
>             v2 = v * 2
>             yield( k, v2)
>         end
>     end
> end
> 
> h = MyHash.new
> h['a'] = 1
> h['b'] = 2
> h['c'] = 3
> h.each do | k, v | puts "#{k}==>#{v}" end
> 
> --
> "It requires wisdom to understand wisdom:
>  the music is nothing if the audience is deaf."
>  - Walter Lippman

-- 
"It requires wisdom to understand wisdom:
 the music is nothing if the audience is deaf."
 - Walter Lippman