From: Erik Veenstra <erikveen@...>
Date: 2008-07-18T10:20:06+09:00
Subject: Re: The next number that is not in an array

> n = ([*n.succ..rn.max.succ]-rn).min || n.succ

Two enhancements

* "min" can be replaced by "first", since a range is ordered.
  "first" is faster.

* "max" returns nil in case of an empty array. Fall back to n.

Enhanced version:

 n = ([*n.succ..(rn.max||n).succ]-rn).first || n.succ

gegroet,
Erik V. - http://www.erikveen.dds.nl/