From: Rob Biedenharn <Rob@...>
Date: 2008-07-17T10:56:57+09:00
Subject: Re: The next number that is not in an array

On Jul 16, 2008, at 9:38 PM, Harry Kakueki wrote:
> On Thu, Jul 17, 2008 at 6:01 AM, Tim Conner  
> <crofty_james@hotmail.com> wrote:
>> I want to increment the current value of a variable to the next  
>> number
>> that does not appear in an array of restricted numbers.
>> e.g.
>> restricted_numbers = [2,3,4,5,8,10,15,29]
>>
>> if the variable is currently storing 11 then I want to increment it  
>> to
>> 12,
>> however if the variable is currently storing 1 then I want to  
>> increment
>> it to 6.
>>
>> How is this done in ruby?
>> Thanks in advance
>>
> # If your range is not too big, you could try this.
> # It is not so efficient, but....
>
> ngnums = [2,3,4,5,8,10,15,29]
> mynum = 1
>
> p (0..100_000).select {|x| x > mynum and ngnums.include?(x) == false} 
> [0]
>
> Harry
>
> -- 
> A Look into Japanese Ruby List in English
> http://www.kakueki.com/ruby/list.html

Change that to:
   p (0..100_000).detect {|x| x > mynum and ngnums.include?(x) == false}

and it doesn't have to go all the way to the end of the range.  You  
can use the alias find if that makes more sense than detect.

   p (0..100_000).find   {|x| x > mynum and ngnums.include?(x) == false}

-Rob

Rob Biedenharn		http://agileconsultingllc.com
Rob@AgileConsultingLLC.com