From: Yossef Mendelssohn <ymendel@...>
Date: 2008-07-08T09:24:13+09:00
Subject: Re: Find matching elements in array



On Jul 7, 1:32 am, Sandor Szücs <sandor.szu...@fu-berlin.de> wrote:
> class Array
>    alias old_include? include?
>    def include?(*args)
>
>      if args.length <= 1
>        old_include?(args)
>      else
>        args.all? do |a|
>          old_include?(a)
>        end
>      end
>    end
> end
>
> puts("#{(0..9).to_a.include?(3,5)}")          # true
> puts("#{('a'..'z').to_a.include?(3,5)}")      # false
> puts("#{('A'..'ZZ').to_a.include?('G','AB')}")# true
>
> regards, Sandor Szücs
> --

Two things:

1) This doesn't work. Try ('a'..'z').to_a.include?('a')
2) The length check isn't necessary. It's sufficient to just use
args.all? { |a|  old_include?(a) }, assuming it's okay that calling
include? with no arguments now returns true.

I like Mikel's set-intersection solution (which, incidentally, is what
I was thinking), assuming once again that the order is important.

--
-yossef