From: Leslie Viljoen <leslieviljoen@...>
Date: 2008-06-27T20:48:13+09:00
Subject: Re: define_method with block

On 6/27/08, Robert Klemme <shortcutter@googlemail.com> wrote:
> 2008/6/27 Leslie Viljoen <leslieviljoen@gmail.com>:
>
>
>  > Is there a way that methods defined with define_method can take a block?
>  > Here's my fighting module:
>  >
>  > module Taikwando
>  >        def self.add_warrior(n)
>  >                define_method(n) do
>  >                        puts "#{n} fights!"
>  >                        yield
>  >                end
>  >        end
>  >
>  >        def fight(*names)
>  >                names.each do |n|
>  >                        Taikwando.add_warrior(n)
>  >                end
>  >        end
>  > end
>  >
>  > include Taikwando
>  >
>  >
>  >
>  > ..when I require it, I can do this:
>  >
>  >>> fight "morpheus", "neo"
>  > => ["morpheus", "neo"]
>  >>> neo do
>  > ?> puts "karate chop!"
>  >>> end
>  > neo fights!
>  > LocalJumpError: no block given
>  >        from ./kungfu.rb:102:in `neo'
>  >        from (irb):5
>  >
>  >
>  > - the yield does not work. Any ideas?
>
>
> AFAIK there is no way (yet) to define a method that needs a block via
>  define_method.  I believe you can try to work around this by doing
>
>  self.class.class_eval "def #{m}; puts '#{m} fights'; yield; end"
>
>  Kind regards
>
>  robert
>

I can explicitly pass a block to my fight method too, but it's so ugly:
neo(lambda do
puts "flying kick"
end
)




>
>  --
>  use.inject do |as, often| as.you_can - without end
>
>


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