From: Clement Ow <clement.ow@...>
Date: 2008-06-25T11:05:11+09:00
Subject: Re: Regex extracting certain characters

Pe単a, Botp wrote:
> From: clement.ow@asia.bnpparibas.com
> # C:/Ruby/20080205/2008
> # C:/Ruby/2008
> # I need a regular expression which can select just 2008 and utilise the
> # string that contains just 2008 instead of 20080205.
> 
> pardon if i'm mistaken, but maybe you may want to get the "ending" part 
> of that pathname w/o using regex,
> 
> eg,
> 
> s
> #=> "C:/Ruby/20080205/2008"
> 
> year=s.split("/").last
> #=> "2008"
> 
> year == "2009"
> #=> false
> 
> year == "2008"
> #=> true
> 
> kind regards -botp

Thank you for all your prompt replies =)

I think I did not explain myself clearer..
What I want to test for is actually just solely '/2008' which can be 
anywhere in the path name, maybe citing some examples would be clearer.

These are the kind of strings i want to test for:
C:/2008/ruby or C:/ruby/test/2008 or C:/ruby/test/2008/testing

These are the kind of strings that I want to eliminate:
C:/20080229/ruby or C:/ruby/test/20080502 or 
C:/ruby/test/20080405/testing or C:/29022008/ruby

In other words, I want to just test for "/" followed by "2008" in a 
given string.

Thanks.

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