From: Petr Dupovnik <petrdupovnik@...>
Date: 2008-06-19T05:05:12+09:00
Subject: regular expression

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Hello

Suppose I have a string with some repeating patterns:

string = "some miscellaneous text [sdfsdf.wer], some more miscellaneous text
[vbnfg.thy], and yet more text [jkhjkhjk.345]"

I want catch all instances of "[.*]" in this line - without the square
brackets. - in the above example that would be 'sdfsdf.wer', 'vbnfg.thy',
and 'jkhjkhjk.345'.

What regular expression would pull each instance of "[.*]" into a separate
element in an array?

my_match=string.match('\[(\w+\.\w{3}\]')

This only catches the first match, and ignores the second and third.

grateful for any help.

Petr.

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