From: "Christoffer Lernö" <lerno@...>
Date: 2008-06-18T23:41:11+09:00
Subject: Re: little problem (google hiring puzzle)

On 15 Jun 2008, at 18:59, ex wrote:

> Hi guys, I wonder if someone can find a pure ruby solution instead of
> mine (I still can get out of my *loop* mind):

This works

a = [4, 3, 2, 1, 2]
x = a.inject([1]) { |sum, i | sum << sum.last * i }
x.pop
y = a.reverse.inject([1]) { |sum, i| sum << sum.last * i }
y.pop
y.reverse!
o = []
a.length.times { |i| o[i] = x[i] * y[i] }
p o