From: Justin To <tekmc@...>
Date: 2008-06-13T07:44:40+09:00
Subject: Re: Trie data structure

  def each
    info = [value,number_exists, children]
    yield(info)
    @children.each do |child_node|
        child_node.each { |e| yield e  }
      end
    end

  def output
    numberCollector = []
    tempString= ''

    each do |x|
      tempString.concat(x[0].to_s)
        if(x[1])
          numberCollector.push(tempString)
          tempString=tempString.chop
        end


    end

    puts numberCollector
  end

Only works for numbers that share (1) common node: e.g. 22, 23, 24, 25

What can I do to output numbers that share (x) common nodes?

Thanks!
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