From: Dustin Barker <dustin.barker@...>
Date: 2008-06-11T08:15:51+09:00
Subject: Re: Basic Tree Data Structure


On Jun 10, 2008, at 6:16 PM, Justin To wrote:

> Your illustration definetely helps. I guess my ultimate confusion  
> comes
> from the last two yields to e:
>
>
> 1. yield e # node b got e='c', so yielding #yielding to t.teach?
> 2. yield e # node a got e='c', so yielding

---------- yield value # node c is yielding 'c'
------ yield e         # node b got e='c', so yielding 'c' to node a
---- yield e           # node a got e='c', so yielding 'c' to t.each

>
>
> For #1, e='c' so why doesn't it yield that 'c' to t.each and puts 'c'

It does, but by way of node b and node a. So let's try with different  
code:

def foo
   bar { |x| yield "foo #{x}" }
end

def bar
   baz { |x| yield "bar #{x}" }
end

def baz
   yield "baz"
end

foo { |x| puts x }

output: foo bar baz

>
>
> You've helped a lot and done all you could. It'll just be up to me to
> try to wrap my mind around it.

No problem - good luck!

-Dustin