From: 7stud -- <bbxx789_05ss@...>
Date: 2008-06-02T04:33:55+09:00
Subject: Re: Remove Parts of a String

Dan __ wrote:
hen display the rating they've given.
> 
> It seems to me that both yours and Stephano's solutions are equally 
> simple for what I'm using them for.  

I disagree.  This solution is an abomination:

str.gsub(/:[^,]*(?:$|(?=,))/,'').split( ',')

Your problem is very simple.  If you split() this string on commas:

"12343:3,73820:1,183874:8"

you get this array:

["12343:3", "73820:1", "183874:8"]

Then you just have to split() each of the strings in the array, e.g 
"12343:3", on the colon:

arr.each do |str|
  results = str.split(/:/)
  p results
end


Here it is altogether:

str = "12343:3,73820:1,183874:8"

arr = str.split(/,/)
p arr

arr.each do |str|
  results = str.split(/:/)
  p results
end

["12343:3", "73820:1", "183874:8"]
["12343", "3"]
["73820", "1"]
["183874", "8"]

Note: it's clearer to write split(",") but as is being discussed in 
another thread, the code will execute faster if you use a regex: 
split(/,/).  If you specify an argument for split(), then use a regex 
rather than a string to make your code more efficient.  If you value 
code clarity more than a slight improvement in efficiency, then use a 
string.






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