From: Boris Schmid <boris@...>
Date: 2008-05-26T19:32:18+09:00
Subject: Re: briefest method of generating a list of random numbers?

> You could also do
> 
>   Array.new(100) { 97 + rand(26) }.pack("c*")
> 
> Peter

Pack seems to be faster than the combination of .chr and join, which is 
a nice side-effect, as I'm running simulations in ruby, and they takes 
aeons of time (well, nearly a week). Don't ask me why I'm using ruby, it 
just sort of happened ;), and the code is only 160 lines, which compares 
favorably to the C ancestor of this simulation (which did more or less 
the same in 4000 lines)


irb(main):017:0> time = Time.new ; 1000.times {string = Array.new(1000) 
{ rand(26) + 97 }.pack("c*")} ; puts Time.new - time
0.184389
=> nil
irb(main):018:0> time = Time.new ; 1000.times {string = Array.new(1000) 
{ (rand(26) + 97).chr }.join} ; puts Time.new - time
0.330891
=> nil

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