From: Victor Reyes <victor.reyes@...>
Date: 2008-05-23T01:27:42+09:00
Subject: Re: Is rdoc (http://www.ruby-doc.org/core/) complete?

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Thank you all.
Jes=FAs, thank you for the code snippet.

On Thu, May 22, 2008 at 10:02 AM, Jes=FAs Gabriel y Gal=E1n <
jgabrielygalan@gmail.com> wrote:

> On Thu, May 22, 2008 at 3:11 PM, Victor Reyes <victor.reyes@gmail.com>
> wrote:
> > Please forgive my ignorance and thank you for the information.
> >
> > I have an array of integers with a minimum of 9 elements and a maximum =
of
> > 81.
> > I need to count the frequency of each digit (1..9).
> > That's why I was looking into the use of *find_all* or some other util
> that
> > would make my code simple. Otherwise I would have to loop and count the
> old
> > fashion way.
> >
>
> This is a typical way:
>
> irb(main):001:0> a =3D [1,2,3,4,3,2,1,2,3,4,5,6,5,4,3,4,5,6,7,8,7,8,9]
> =3D> [1, 2, 3, 4, 3, 2, 1, 2, 3, 4, 5, 6, 5, 4, 3, 4, 5, 6, 7, 8, 7, 8, 9=
]
> irb(main):002:0> h =3D Hash.new {|h,k| h[k] =3D 0}
> =3D> {}
> irb(main):003:0> a.each {|x| h[x] +=3D 1}
> =3D> [1, 2, 3, 4, 3, 2, 1, 2, 3, 4, 5, 6, 5, 4, 3, 4, 5, 6, 7, 8, 7, 8, 9=
]
> irb(main):004:0> h
> =3D> {5=3D>3, 6=3D>2, 1=3D>2, 7=3D>2, 2=3D>3, 8=3D>2, 3=3D>4, 9=3D>1, 4=
=3D>4}
>
> or:
>
> irb(main):005:0> h2 =3D Hash.new(0)
> =3D> {}
> irb(main):006:0> a.each {|x| h2[x] +=3D 1}
> =3D> [1, 2, 3, 4, 3, 2, 1, 2, 3, 4, 5, 6, 5, 4, 3, 4, 5, 6, 7, 8, 7, 8, 9=
]
> irb(main):007:0> h2
> =3D> {5=3D>3, 6=3D>2, 1=3D>2, 7=3D>2, 2=3D>3, 8=3D>2, 3=3D>4, 9=3D>1, 4=
=3D>4}
>
>
>
> Jesus.
>
>

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