From: "David A. Black" <dblack@...>
Date: 2008-05-09T10:04:12+09:00
Subject: Re: Doing an AND in regexp char class

Hi --

On Fri, 9 May 2008, Joel VanderWerf wrote:

> David A. Black wrote:
>>> irb(main):013:0> /(?=.*h)(?=.*o)/ === "h o"
>>> => true
>> 
>> That depends on the order, though.
>
> Yes, it's buggy. Should use //m:
>
> irb(main):003:0>  /(?=.*h)(?=.*o)/ === "o \nh"
> => false
> irb(main):004:0>  /(?=.*h)(?=.*o)/m === "o \nh"
> => true
>
> Does that fix the order problem you were thinking of?

Actually I think I was wrong about the order mattering (since they're
zero-width). But /m helps anyway.  I still think you could just change
the roles of the two strings and dissect "the string" as a character
class and "the characters" as a string, and use your original
technique.


David

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