From: Todd Benson <caduceass@...>
Date: 2008-05-09T00:52:05+09:00
Subject: Re: Check if char in string?

On Thu, May 8, 2008 at 8:12 AM, Heesob Park <phasis@gmail.com> wrote:
> Hi,
>
> globalrev wrote:
>> ty all for the help. haesob park did what iw anted.
>>
>> this is the program i wrote, it  is an encrypter/decrypter for the
>> robbers language(r�varspr�ket in swedish), its from the book Kalle
>> Blomkvist by late and very famous author Astrid Lindgren.
>> you add o + the consonant, nothing is done to vowels.
>> so d becomes dod, a is just a.
>>
>> dad is therefore dodadod, super is sosupoperor etc.
>>
>>
>>
>> puts "Enter sentence to encrypt: "
>> str = gets
>>
>> enc = ""
>> for x in (0..str.length()-1)
>>   if str[x].chr =~ /[qwrtpsdfghjklzxcvbnm]/
>>       enc = enc + str[x].chr + "o" + str[x].chr
>>   else
>>       enc = enc +str[x].chr
>>   end
>> end
>>
>> print enc
>>
>>
>>
>> puts "Enter code to decrypt: "
>> code = gets
>>
>> x = 0
>> dec = ""
>> while (x<code.length())
>>   dec = dec + code[x].chr
>>   if code[x].chr =~ /[qwrtpsdfghjklzxcvbnm]/
>>     x = x + 2
>>   end
>>   x = x + 1
>> end
>>
>> print dec
>>
>>
>>
>> i then changed to !~ just like haesob said but if i do /aeiouy / it
>> doesnt react to space " ". how do i get it to treat " " as "a"?
> You can do with like this:
> if str[x].chr !~ /[\saeiouy]/
>
> BTW, your encryption equals to
> str.gsub(/([^\saeiouy])/,"\\1o\\1")

Not quite.  [^\saeiouy] is not the same as the set of consonants.

Todd