From: Raghu Go <rgowka1@...>
Date: 2008-04-26T23:37:26+09:00
Subject: Re: All occurances of a  character in a string

I did a quick test and like Siep's modifications..

Method1 Time elapsed: 0.236999988555908 milliseconds

Siep's modification Method2 Time elapsed: 0.123999834060669 milliseconds


def method1(a)
  i = 0
  ret = Hash.new
  a.scan(/./) {|c|
    ret[c] = ret[c].nil? ? [i] : ret[c] << i
    i = i + 1
  }
  p a
  p ret
end

def method2(str) #Siep
  ar = str.split("")
  result = Hash.new{Array.new}

  ar.each_with_index do|item,index|
    result[item] = result[item]<<index
  end
  result.each{|k,v| puts k +  " = " + v.join(",")}
end

Siep Korteling wrote:
> S2 wrote:
>> S2 wrote:
>> 
>>> irb(main):006:1>   ret[c] = ret[c].nil? ? d : d << ret[c]
>>> irb(main):007:1>   ret[c].flatten!
>> 
>> oh sorry, here are a few things that are not needed:
>> a = "abbccdaab"
>> i = 0
>> ret = Hash.new
>> a.scan(/./) {|c|
>>   ret[c] = ret[c].nil? ? [i] : ret[c] << i
>>   i = i + 1
>> }
>> p a
>> p ret
> 
> The block form of Hash.new gets rid of the if-statement; like this:
> 
> str = "abbccdaab"
> ar = str.split("")
> result = Hash.new{Array.new}
> 
> ar.each_with_index do|item,index|
>   result[item] = result[item]<<index
> end
> 
> result.each{|k,v| puts k +  " = " + v.join(",")}
> 
> regards,
> 
> Siep

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