From: Peter Szinek <peter@...>
Date: 2008-04-26T22:57:04+09:00
Subject: Re: All occurances of a  character in a string

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Hi Raghu

My 2-minute horrible-hack(tm):

input = "abbccdaab"
i = 0;
input.split('').inject({}) {|a,v| a[v] = a[v] ? (a[v] <<  
input[i..-1].index(v)+i) : [input[i..-1].index(v)+i]; i+=1; a}

{"a"=>[0, 6, 7], "b"=>[1, 2, 8], "c"=>[3, 4], "d"=>[5]}

I am sure there has to be a *MUCH* nicer way though, because this is  
rather ugly...

Cheers,
Peter
___
http://www.rubyrailways.com
http://scrubyt.org

On Apr 26, 2008, at 2:55 PM, Raghu Go wrote:

> Hi - I am trying to figure out the ruby way of printing all occurances
> of a character in a string..
>
> The index method on string gives only the first occurance only.
>
> Example input string - abbccdaab
> desired output - 'a' = 0 6 7
>                 'b' = 1 2 8
>                 'c' = 3 4
>                 'd' = 5
>
> Any help greatly appreciated..
> -- 
> Posted via http://www.ruby-forum.com/.
>


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