From: Clement Ow <clement.ow@...>
Date: 2008-04-23T19:08:23+09:00
Subject: Re: Extract date from filenames using regex

Jes炭s Gabriel y Gal叩n wrote:
> On Wed, Apr 23, 2008 at 11:01 AM, Clement Ow
> <clement.ow@asia.bnpparibas.com> wrote:
>>
>>           size = (File.size(file))/1024
>>   end #if
>>
>>  >>I do have files with different date formats, but the format yyyymmdd works when i use DateTime.parse maybe
>> because DateTime accepts this format?
> 
> Yes, that's exactly the issue.
> 
>> however if i use strptime it also cant work. Any help will be greatly appreciated =)
> 
> If you have files with different formats, you will have to know which
> format each file is, because DateTime.parse is expecting yyyymmdd,
> while strptime is expecting whatever format you pass it, but only one
> format. If the dates are current dates, and are only these two formats
> (yyyymmdd or ddmmyyyy) I think this is safe:
> 
> regexp = /(\d{8})/
> match = regexp.match(file_name)
> file_date = nil
> begin
>   file_date = DateTime.parse(match[1])
> rescue ArgumentError
>   file_date = DateTime.strptime(match[1], "%d%M%Y")
> end
> 
> However, if you have arbitrary dates, this can lead to unexpected
> results. For example:
> 
> 19011902
> 
> will result in 1901-19-02 while maybe you meant 19-01-1902.
> Also, I think the above is safe because the century (20xx for the
> year) is not a valid month, but there might be some corner case I
> haven't realized.
> 
> Jesus.

Hey Jesus,

 file_date = DateTime.strptime(match[1], "%d%M%Y")
when the above is being put, it will parse the date as eg.28012008 even 
thought the date is 28032008. So, I tried some trail and error and i 
used this:
 file_date = DateTime.strptime(match[1], "%d%m%Y")
and bingo, it parses the date correctly and thus being able to run the 
command to delete. Thanks alot for your time and help! =)

Cheers!
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