From: "Jesús Gabriel y Galán" <jgabrielygalan@...>
Date: 2008-04-23T17:47:26+09:00
Subject: Re: Extract date from filenames using regex

On Wed, Apr 23, 2008 at 10:38 AM, Clement Ow
<clement.ow@asia.bnpparibas.com> wrote:
> Jesús Gabriel y Galán wrote:
>
>
> > On Wed, Apr 23, 2008 at 9:50 AM, Jes?briel y
>  > Galᮦlt;jgabrielygalan@gmail.com> wrote:
>  >> On Wed, Apr 23, 2008 at 9:14 AM, Clement Ow
>  >>
>  >> <clement.ow@asia.bnpparibas.com> wrote:
>  >
>  >>  1.- Change DateTime.parse to DateTime.strptime passing a format
>  >>  that describes where in the string you have the two digits of the day, the month
>  >>  and the four digits of the date. I haven't been able to gather a quick example,
>  >>  cause I don't find a reference for the format string (any help here
>  >>  appreciated).
>  >>  The doc refers me to the date/format.rb for details and I don't see
>  >>  anything clear
>  >>  there.
>  >
>  > After a couple of trial/error tests this seems to work:
>  >
>  > DateTime.strptime "16042008", "%d%M%Y"
>  >
>  > So any of the two solutions will work for you.
>  >
>  > Jesus.
>
>
>  Hi Jesus,
>  First of all thanks for your help!
>  However,
>  Despite using
>  d= DateTime.civil (match[1].to_i, match[2].to_i, match[3].to_i)
>           file_date=d.to_s
>  OR
>
>  file_date = DateTime.strptime (match[1], "%d%M%Y")
>
>  it still gives me invalid date as the error msg. But when i run it in
>  the fxri it seems to work fine.. This only seems to happen when the date
>  format is ddmmyyyy, but for yyyymmdd it has no problems though.. Any
>  ideas anyone? I have cracked my head but to no avail.

Can you post the smallest example that fails? Do you have files with
different date formats?

Jesus.