From: Robert Dober <robert.dober@...>
Date: 2008-04-05T22:26:17+09:00
Subject: Re: The ||= assignment operator

On Sat, Apr 5, 2008 at 2:40 PM, David A. Black <dblack@rubypal.com> wrote:
> Hi --
>
>
>  On Sat, 5 Apr 2008, Robert Dober wrote:
>
>
> > Furthermore things are simple
> >
> > (1) lval ||= rval  is lval = lval || rval
> >
>
>  I think you mean:
>
>   lval || lval = rval
>
>  (See the hash default case which flushes this out.)
Wow David, as they say "A little knowledge is a dangerous thing", well
as I said ignorants like me teaching nonsense :(

Thx for correcting me David.

Cheers
Robert
>
>
>
>
>  David
>
>  --
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>



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