From: "David A. Black" <dblack@...>
Date: 2008-04-05T21:40:47+09:00
Subject: Re: The ||= assignment operator

Hi --

On Sat, 5 Apr 2008, Robert Dober wrote:

> Furthermore things are simple
>
> (1) lval ||= rval  is lval = lval || rval

I think you mean:

   lval || lval = rval

(See the hash default case which flushes this out.)


David

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