From: Robert Klemme <shortcutter@...>
Date: 2008-03-31T06:53:07+09:00
Subject: Re: rexml to slow

On 30.03.2008 22:21, Bu Mihai wrote:
> Robert Klemme wrote:
>> On 30.03.2008 20:23, Bu Mihai wrote:
>>> this is the criteria:
>>>
>>>  node=rexml_element.find_first_recursive {|node| 
>>> node.attributes["again"]=="yes"}
>> That's easy
>>
>> doc.elements.each('//[@again="yes"]') do |node|
>>    # any node that has attribute again with value yes
>> end
>>
>> And I am pretty sure that this is faster than your approach.  What does
>> your program do?  With more context we can come up with further 
>> suggestions.
> 
> I'm not sure if that will works, i have a xml file with this 
> structure(and it must be like this, the following example is a simple 
> sample of the original):
> <root>
>    <new_section>
>       <pages>
>            <page again="yes">page1</page>
>            <page again="no">page2</page>
>            <page againe=yes"">page3
>                  <pages>
>                     <page again="no">page4<page>
>                     <page again="yes">
>                        <pages>....and so on
>                  </pages>
>            </page>
> 
>       </pages>
>    </new_section>
>    <new_section>
> </root>
> 
> I have a recursive function to find all 'page' nodes with attribute 
> 'again' 'yes but i need to start the searc from the beging of the file 
> or from the current node and the display all subnodes with 'yes';

You can use the XPath from the root and I believe also from a 
particulara node.

> after 
> the all nodes was founded then i need to search them again from the 
> begining of the file;

When I asked what your program does, I really meant: Can you explain in 
non technical words what this program is supposed to do?  Since you seem 
to traverse over the same nodes over and over again I have the strong 
feeling that there is a better alternative - but for that we need to 
know the purpose of the program.

> Many thanks for your help Robert.

You're welcome.

Kind regards

	robert