From: Stefano Crocco <stefano.crocco@...>
Date: 2008-03-24T18:44:49+09:00
Subject: Re: Question about Array#*

On Monday 24 March 2008, Magicloud Magiclouds wrote:
> Hello,
> 	In `ri 'Array#*'`, it says that the result is the concatenation of
> copies of self if the argument is an int.
> 	So, it is "COPY".
> 	Then why something like '[[0]] * 10', returns an array, that each
> element is a pointer to the first element?
> 	Does this mean "copy of an Array" is just a duplicated pointer?
>
> Thanks.

I think that here the word "copy" has the same meaning it has in clone and 
dup, that is it means a shallow copy: the array itself is copied, but its 
contents aren't. In other words, what you get using Array#* with a number is 
an array of size n times the original one, whose contents are the contents of 
the original array repeated n times.

I hope this helps

Stefano