From: Magicloud Magiclouds <magicloud.magiclouds@...>
Date: 2008-03-24T18:34:12+09:00
Subject: Question about Array#*

Hello,
	In `ri 'Array#*'`, it says that the result is the concatenation of 
copies of self if the argument is an int.
	So, it is "COPY".
	Then why something like '[[0]] * 10', returns an array, that each 
element is a pointer to the first element?
	Does this mean "copy of an Array" is just a duplicated pointer?

Thanks.