From: Todd Benson <caduceass@...>
Date: 2008-03-05T16:26:32+09:00
Subject: Re: Newbea question again?

On Tue, Mar 4, 2008 at 10:29 PM, Ibrahim Dogru <casid3@lycos.com> wrote:
> Hello Ruby Developers,
>
>  I have tiny problem about comparison. I have a array and hash. I want to
>  compare array elements with hash keys.
>  more details:
>  this is my hash, I create it from yaml file
>  my yaml file
>  template1:
>   template_of_roster3: template_of_roster2
>   template_of_roster4: template_of_roster3
>
>
>  @get_config=YAML.load(File.open("#{PATH_IM}/config/converter.yml"))
>     @get_config  == Hash
>   @my_hash==Hash
>  @enterprises=@get_config["template1"]
>
>  and my array
>  @my_array=["template_of_roster","template_of_roster2","template_of_roster3"]
>
>  my question here is that how can I compare array with hash keys and how
>  can I can send warning message to user?
>  @my_array.eql?(@my_hash.key)==false
>  warn "warning message"
>
>  something like this.
>
>  thanks..

You have a strange structure here.  You have values that act as keys.
4 -> 3 and 3 -> 2.  But, if it won't be circular, and your hashes are
truly nested, then, here's a cowboy recursive hack...

@b = false
def check h, key
  h.each { |k, h| @b ||= h.keys.include?(key) || check(h, key) rescue false; @b}
end

hsh = YAML.load_file("your_file.yml")
puts check(hsh, "template_of_roster")
puts check(hsh, "template_of_roster3")

=> false
=> true

If your hashes are not nested (i.e. you have one level that you are
concerned about), then all you should just use use
h["template1"].keys.include?

hth,
Todd