From: Thomas Wieczorek <wieczo.yo@...>
Date: 2008-03-04T09:52:31+09:00
Subject: Re: Why is this not implemented in Ruby

On Mon, Mar 3, 2008 at 10:36 PM, Jason Roelofs <jameskilton@gmail.com> wrote:
> Show me a language that does allow you to do this, I've never seen it.
>  Even then, Ruby doesn't deal with method overloads via parameter
>  lists, so there's a fundamental reason why it won't work:
>
>  def foo(a)
>  end
>
>  def foo(a, b)
>  end
>
>  def foo(a, b, c)
>  end
>
>  foo(1) # => ArgumentError: wrong number of arguments (1 for 3)
>
>
>  Ruby 1.9 has keyword arguments, so you'll be able to get past that
>  easily then. You can fake it in 1.8 with a hash:
>
>  def aProc(options = {})
>   a = options[:a] || 5
>   b = options[:b] || 6
>   c = options[:c] || 7
>   print a, b, c
>  end
>
>  aProc(:a => 1, :c => 3)
>
>  With Ruby 1.9 that will look like (I think, doing this from memory):
>
>  aProc(a: 1, c: 3)
>
>  Jason
>
>
>
>  On Mon, Mar 3, 2008 at 4:27 PM, Damjan Rems <d_rems@yahoo.com> wrote:
>  >
>  >  It is probably a good reason but why is this not implemented in ruby.
>  >
>  >  irb(main):005:0> def aProc(a=5,b=6,c=7)
>  >  irb(main):006:1> print a,b,c
>  >  irb(main):007:1> end
>  >  irb(main):008:0> aProc
>  >  567=> nil
>  >
>  >  irb(main):009:0> aProc(1,,3)
>  >  SyntaxError: compile error
>  >  (irb):9: syntax error, unexpected ','
>  >  aProc(1,,3)
>  >          ^
>  >         from (irb):9
>  >         from :0
>  >
>  >  Why oh why I can not omit parameter in the middle of statement? I am
>  >  forced to know its default value if I want to omit a parameter in the
>  >  middle or at the begining of the statement.
>  >
>  >
>  >  by
>  >  TheR
>  >  --
>  >  Posted via http://www.ruby-forum.com/.
>  >
>  >
>
>