From: Justin Collins <justincollins@...>
Date: 2008-02-28T04:01:56+09:00
Subject: Re: Multithreading problem

Venkat Bagam wrote:
> Hi All,
>
>            I am pretty much a starter in multi-threading. In one of my
> application, I needed to run three threads along each other. Here is my
> code
>
> require 'rubygems'
> require 'mechanize'
> require 'fileutils'
> require 'timeout'
>
> agent = WWW::Mechanize.new
>
> start_time = Time.now
> threads = []
>
>   threads << Thread.new do
>                 puts "running thread1"
>                 start = 0
>     count = 10
>     finish = 30
>     while start < finish
>       page_links = Array.new
>       parent_url = "http://www.rknowsys.com"
>       page = agent.get(parent_url)
>       page = nil
>       start += count
>     end
>     puts "thread1 completed" if start == finish
>   end
>
>   threads << Thread.new do
>     puts "running thread2"
>     start = 30
>     count = 10
>     finish = 60
>     while start < finish
>       page_links = Array.new
>       parent_url = "http://www.rknowsys.com"
>       page = agent.get(parent_url)
>       page = nil
>       start += count
>       raise "stopped bcaz start > 40" if start > 40
>     end
>     puts "thread2 completed" if start == finish
>   end
>
>   threads.each do |thread|
>     begin
>       thread.join
>     rescue RuntimeError => e
>       puts e.message
>     end
>   end
>
> end_time = Time.now
> interval = end_time - start_time
> puts interval
>
> the above code prints the error message, at the time of each thread join
> and stops.
> But, How do I deal with such a scenario that the thread2 continues to
> run again setting its local variable start = 30 ?
>
> Any help appreciated.
>
> regards,
> Venkat Bagam
>   

What is the error message?