From: Rick DeNatale <rick.denatale@...>
Date: 2008-02-28T02:35:00+09:00
Subject: Re: Math problem

On 2/27/08, Thomas Preymesser <thopre@gmail.com> wrote:
> On 26/02/2008, grandmabeckie@msn.com <grandmabeckie@msn.com> wrote:
>  >
>  > I am try to help my daughter:
>  > Problem
>  >
>  > father is 4 times older then his daughter.
>  > in 6 years he will be 3 times older what is the answer and how did you
>  > reach it.
>
>
>
> 48 and 12
>
>  def all_conditions(f,d)
>   f == 4*d and f+6 == (d+6)*3
>  end
>
>  loop do
>   daughter = rand(father = rand(100))
>   if all_conditions(father,daughter)
>     puts "father: #{father} daughter: #{daughter}"
>     break
>   end
>  end

Not exactly the fastest way to do it empirically, why random.

d = 0
d += 1 until (f = 4*d) && (f + 6) == (d + 6) * 3
puts "Father is #{f} years old, Daughter is #{d}."


-- 
Rick DeNatale

My blog on Ruby
http://talklikeaduck.denhaven2.com/