From: Gregory Marton <q8pb97u001@...>
Date: 2008-02-24T23:19:26+09:00
Subject: Re: passing method references in python & ruby

Another potentially easy question:

I'd like to pass a surround method into another, where the surround 
method would take a block, and should yield to it, perhaps doing stuff 
before and after.  This is not a real call/cc surround, just something 
simple.  So:

def do_things(options={})
  opts = {:surround => Proc.new{yield}}.merge(options)
  opts[:surround] do
    the actual task
  end
end

except this doesn't actually work with Procs, because opts[:surround] is 
an undefined method, of course.  It contains a method reference.  Well, 
rather, a procedure reference.  In any case, I want to invoke it with a 
block.

so I think
  y = lambda{ yield }
  y.call{ 3 }
perhaps, but no:
LocalJumpError: no block given

How shall I pass it a block?

Thanks,
Grem
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