From: Mark Bush <mark@...>
Date: 2008-02-23T05:12:48+09:00
Subject: Re: Regex in Ruby question

ThoML wrote:
> There are of course situations when this isn't possible.

require 'strscan'
#                      0         1         2         3
#                      0123456789012345678901234567890123456789
s = StringScanner.new('obar blabar oofbar foobar ofobar offbar')
#                                 ^      ^             ^      ^
until s.eos?
    m = s.scan_until(/([^o]|[^o]o|[^f]oo)(bar)/)
    p s.pos
end

# =>
11
18
32
39

:-(
However, with:
    m = s.scan_until(/(([^o]|^)|([^o]|^)o|([^f]|^)oo)(bar)/)

=>
4
11
18
32
39

:-)
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