From: Mark Bush <mark@...>
Date: 2008-02-21T22:38:35+09:00
Subject: Re: How to get the directory of the current script?

> File.dirname(__FILE__) will give you the current file's path.

The current file may be accessed with a relative path.  If you need the 
absolute path,
make sure you expand it: File.expand_path(File.dirname(__FILE__))

> Also, if I have a module, within a function, how do I get the parent
> directory (full path) of that module?

If __FILE__ is used in that module, it will refer to the file containing 
that module.
If the module is under your control, you can add a method that provides 
this:

module MyModule
  def this_file
    __FILE__
  end
end

Otherwise, as has been noted, since a module name does not have to have 
any
relation to the filename it is in, there is no way (AFAIK) to find the 
file containing a
particular module unless you open the current file and parse for any 
require
or load calls (recursively using the current environment for searching 
for files)
and look for the module declaration line.  (Note that a file may have 
been required
using a path, so you must parse the current script to find where files 
have been
located.)

Of course, a module could have content added in multiple files...
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