From: 7stud -- <bbxx789_05ss@...>
Date: 2008-02-20T14:20:41+09:00
Subject: Re: optparse: parse v. parse!  ??

7stud -- wrote:
> Nobuyoshi Nakada wrote:
>> Hi,
>> 
>> At Wed, 20 Feb 2008 11:57:09 +0900,
>> 7stud -- wrote in [ruby-talk:291731]:
>>> which indicates that none of the on() handlers executed.  My reading of
>>> parse() is that it's the same as parse!() except that parse() doesn't
>>> remove the option/values from ARGV.
>> 
>> No, parse doesn't have default arguments.  
> 
> Huh?

Well, after scanning through the docs again, I found this in one of the 
examples:

options = OptparseExample.parse(ARGV)

...and now your cryptic post makes sense.


Usage
------

opts.parse!    #removes options/values from ARGV

opts.parse(ARGV)    #doesn't change ARGV
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