From: 7stud -- <bbxx789_05ss@...>
Date: 2008-02-20T11:57:09+09:00
Subject: optparse: parse v. parse!  ??

Here's a simple example that looks for two options--one with a required
value and one with an optional value:

require 'optparse'

opts = OptionParser.new do |opts|
  puts 'hello'

  #option where value is required:
  opts.on("-t=RANDOM_CHARS") do |val|
    puts 'in first on()'

    puts "-t option entered with value=#{val}"
  end

  #option where value is optional:
  opts.on("-y [=RANDOM_CHARS]") do |val|
    puts "-y option entered with value=#{val}"
  end

end

opts.parse!
p ARGV

--output:--
$ruby optparseEx2.rb -t hi -y

hello
in first on()
-t option entered with value=hi
-y option entered with value=
[]


However, when I change the line:

opts.parse!

to:

opts.parse

I get this output:

$ruby optparseEx2.rb -t hi -y

hello
["-t", "hi", "-y"]

which indicates that none of the on() handlers executed.  My reading of
parse() is that it's the same as parse!() except that parse() doesn't
remove the option/values from ARGV.
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