From: Sebastian Hungerecker <sepp2k@...>
Date: 2008-01-31T06:42:53+09:00
Subject: Re: Ruby Puzzle Challenge

Dominik Honnef wrote:
> > p *1..100
>
> Would you be so gentle and explain this piece of code to me?
> [...] isn't * a binary operator? I 


* can be a binary operator, yes, but here it is the unary, prefix 
splat-operator which takes an array or any object that responds to
to_a and turns it into a list of arguments:
foo(*[:la,:li,:lu])  becomes  foo(:la,:li,:lu)
p *1..5  becomes  p 1,2,3,4,5


HTH,
Sebastian
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