From: 7stud -- <bbxx789_05ss@...>
Date: 2008-01-25T05:02:08+09:00
Subject: Re: why must I initialize this variable?

Gary Wright wrote:
> Execution isn't moving backwards.  You have to think of it as a two
> step process, parsing then execution.  The parser is going to prepare:
> 
>   puts "#{hi}" if (hi = "hello")
>          puts hi
> 
> is such a way that the execution step sees:
> 
>         if (hi = "hello")
>            puts "#{hi}"
>         end
>         puts hi
> 
> So during execution, nothing is going backwards.  But the parser has
> already tagged various parts of the code such that the 'hi' token in
> the conditional is an local variable assignment from a literal (thus
> the warning), the 'hi' token in the then clause as a method call, and
> the 'hi' token on the final puts as a local variable.
> 
> These three issues
> 1) 0-argument method calls and local variables
>     are syntactically identical
> 2) local variables don't have to be declared.
> 3) Ruby's if/unless modifiers imply execution
>     order that is backwards from textual order
> 

Thanks for the detailed explanation.  :)

> Another corner case is

Yep, I already know about that one.
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