From: Wirianto Djunaidi <wirianto.djunaidi@...>
Date: 2008-01-11T07:53:07+09:00
Subject: Re: Execution stops once exception is fired

Mauricio Gonzales wrote:
> Clifford Heath wrote:
>   
>> Mauricio Gonzales wrote:
>>     
>>>   object.method3()
>>> rescue => e
>>>   puts e
>>> end
>>>
>>> and never executes the method3()
>>>       
>> That's the way it's meant to work, it's just what exceptions are,
>> non-local "goto"s to a handler. If you want method3 always to be
>> called, put it in a "finally" clause.
>>
>> Clifford Heath.
>>     
> That's probably will be a solution but the problem is that i don't know 
> when the exception is raised and neither in what method or how many 
> methods will be, well thx anyway for your help, cya
>
>   
If that is the behavior that you wanted, then you will need to wrap each 
method call in begin..rescue block individually.
One way to do it just create a wrapper method to reduce verbosity, like 
this:

def wrapper(&block)
  begin
    block.call
  rescue => e
    puts e
  end
end

wrapper { object.method1 }
wrapper { object.method2 }
wrapper { object.method3 }

I'm sure there are many other way to achieve the same things, such as 
using more advance metaprogramming which I'm still not at that level yet 
or use aspect oriented technique.

-DJ