From: botp <botpena@...>
Date: 2008-01-08T13:36:19+09:00
Subject: Re: proc to block

On Jan 8, 2008 12:06 PM, L A <loren.abrams@yahoo.com> wrote:
> Is there a way to turn a Proc into a block for the purposes of methods that yield to blocks?  It's not a necessity as I can always wrap the Proc in a block, I'm just curious.

maybe use the & op, like

p=proc{"hi, i'm proc"}
#=> #<Proc:0x028cc40c@(irb):1>
p.call
#=> "hi, i'm proc"
def q
  yield
end
#=> nil
q
LocalJumpError: no block given
        from (irb):7:in `q'
        from (irb):9
        from :0
q &p
#=> "hi, i'm proc"
(proc &p).call
#=> "hi, i'm proc"

i am not sure why you want to wrap a proc with a block though

proc {p}
#=> #<Proc:0x02898418@(irb):30>
(proc {p}).call
#=> #<Proc:0x028cc40c@(irb):1>
(proc {p}).call.call
#=> "hi, i'm proc"

kind regards -botp