From: MenTaLguY <mental@...>
Date: 2008-01-04T09:13:17+09:00
Subject: Re: Troubles with blocks

On Fri, 4 Jan 2008 08:49:54 +0900, Holden Holden <pyarnau@gmail.com> wrote:
> Python:
> 
> list(enumerate(['a','b','c']))
> => [(0, 'a'), (1, 'b'), (2, 'c')]
> 
> Ruby:
> 
> t = []; ['a','b','c'].each_with_index { |*x| t << x }; t
> => [["a", 0], ["b", 1], ["c", 2]]
> 
> Which is a very ugly solution. How could I do this on Ruby without a
> temporal variable?

Try this (you will need to require 'enumerator'):

  ['a','b','c'].enum_with_index.to_a

-mental