From: Andre Nathan <andre@...>
Date: 2007-12-30T07:12:03+09:00
Subject: Re: Using "sort!" in a C extension (1.9 problem)

My example was a bit contrieved because I could just have used #sort
without a block. What I'm actually doing is sorting an array by the
length of its elements, which are also arrays. That's why I need the
block version of #sort.

On Sun, 2007-12-30 at 02:49 +0900, Andre Nathan wrote:
> Hello
> 
> In ruby 1.8, I could use Array#sort! in a C extension like this:
> 
> static VALUE
> call_sort_bang(VALUE ary)
> {
>     return rb_funcall(ary, rb_intern("sort!"), 0);
> }
> 
> static VALUE
> sort_i(VALUE ary)
> {
>     long v1 = FIX2LONG(RARRAY_PTR(ary)[0]);
>     long v2 = FIX2LONG(RARRAY_PTR(ary)[1]);
>     return LONG2FIX(v1 - v2);
> }
> 
> static VALUE
> foo(void)
> {
>     VALUE ary = rb_ary_new();
>     rb_ary_push(ary, INT2FIX(1));
>     rb_ary_push(ary, INT2FIX(0));
>     rb_ary_push(ary, INT2FIX(2));
>     rb_iterate(call_sort_bang, ary, sort_i, 0);
>     rb_funcall(rb_mKernel, rb_intern("p"), 1, ary);
>     return a;
> }
> 
> This would print "[0, 1, 2]" as expected. However, it doesn't work in
> ruby1.9 compiled from svn (checked out today). The problem seems to be
> that only one of the array elements is being passed to sort_i(), instead
> of a pair of elements as it's done in 1.8.
> 
> What is the correct way to do this in 1.9?
> 
> 
> Thanks in advance,
> Andre
> 
>