From: Bryan Richardson <btricha@...>
Date: 2007-12-21T08:46:44+09:00
Subject: Re: OptionParser Question

------=_Part_7696_7265279.1198194401518
Content-Type: text/plain; charset=ISO-8859-1
Content-Transfer-Encoding: 7bit
Content-Disposition: inline

Ah yes... this worked great!!!!  Thanks! -- BTR

On Dec 20, 2007 1:20 PM, Stefano Crocco <stefano.crocco@alice.it> wrote:

> Alle Thursday 20 December 2007, Bryan Richardson ha scritto:
> > Hello all,
> >
> > I'm using OptionParser to parse command line options.  I've figured out
> how
> > to handle options for each flag (i.e. opts.on('--port PORT')), but I'm
> not
> > sure how to handle command line arguments that aren't associated with a
> > flag.  For example, say I wanted to parse a file with my file_parser
> > executable using a certain type of parser.  I'd like to say "file_parser
> > --type CDF <file_name>".  I know how to get the type of parser to use
> (see
> > above), but I'm not so sure how to easily get the name of the file I
> want
> > to parse.
> >
> > Any suggestions?  Thanks! -- BTR
>
> Command line arguments (that is, those not associated with an option) can
> be obtained in a different way, depending on wheter you use
> OptionParser#parse or OptionParser#parse!. The former returns an array with
> all the arguments; the second modifies its argument, removing all the
> options (and their arguments) and leaving only the command line arguments.
> For example:
>
> require 'optparse'
>
> options= {}
> o = OptionParser.new do |o|
>  o.on('--type TYPE', 'Use TYPE parser'){|t| options[:type]=t}
> end
>
> args = o.parse ARGV
> puts "The arguments are #{args.inspect}"
>
> If you want to use parse!, replace the last two lines with:
>
> o.parse! ARGV
> puts "The arguments are #{ARGV.inspect}"
>
> I hope this helps
>
> Stefano

------=_Part_7696_7265279.1198194401518--