From: Trans <transfire@...>
Date: 2007-12-17T21:52:21+09:00
Subject: Re: Is there any way to pass further the "hidden" block?



On Dec 17, 3:11 am, "Chiyuan Zhang" <plus...@gmail.com> wrote:
> Like this:
>
> def foo
>   yield
> end
>
> def bar(&brk)
>   foo(&brk)
> end
>
> bar { puts "foo" }
>
> What I want to know is: is there any way to define `bar' like this:
>
> def bar
>   foo
> end
>
> so that foo will get the block passed to bar? I want to know this
> because I learn fromhttp://www.pluralsight.com/blogs/dbox/archive/2006/05/09/23068.aspx
> that the implicit block is much faster than explicitly passing it
> as &brk . I know one solution is
>
> def bar
>   foo { yield }
> end
>
> but that create another block, not the original one.

Do you mean, is there a keyword #block to go along with #block_given?
and #yield? As far as I know, there is no way to pass the block except
via an explicit reference.

But I think explicit may be the future. I'm pretty sure I've heard
some chatter about getting rid of #block_given? Technically I would
think it possible to all but eliminate the speed difference between
explicit and implicit --3x seems very high.

T.