From: Chiyuan Zhang <pluskid@...>
Date: 2007-12-17T17:11:50+09:00
Subject: Is there any way to pass further the "hidden" block?

Like this:

def foo
  yield
end

def bar(&brk)
  foo(&brk)
end

bar { puts "foo" }

What I want to know is: is there any way to define `bar' like this:

def bar
  foo
end

so that foo will get the block passed to bar? I want to know this
because I learn from
http://www.pluralsight.com/blogs/dbox/archive/2006/05/09/23068.aspx
that the implicit block is much faster than explicitly passing it
as &brk . I know one solution is

def bar
  foo { yield }
end

but that create another block, not the original one.