From: Daniel Peikes <danpeikes@...>
Date: 2007-12-16T15:18:32+09:00
Subject: Re: How t owrite an OR statement

Joseph Pecoraro wrote:
>> while again != "y" || "n"
> 
> 
> These don't use the OR logic, but they are similiar.
> until again ~= /^[yn]/i do
>   ...
> end
> 
> Or if your wanted to keep the while keyword you could do this as:
> while again[0] != /^[^yn]/i do
>   ...
> end
> 
> 
> I don't know if you can do exactly what you are trying to do with that 
> syntax.  You can reconstruct the logic like this:
> while again != "y" && again != "n" do
>   ...
> end
> 
> 
> Here is another approach more along the lines of what you have (is 
> something in a list of something else), likewise the until loop could be 
> made a while loop:
> good_chars = %w(y n) #=> ['y', 'n']
> until good_chars.include? again do
>   ...
> end

This is what I currently have, but it looks to be giving me an infinite 
loop:
again = "y"
number = []

while  again == "y"


  puts "Please enter a number."

  number = gets.chomp

  puts "Would you like to enter a number again? y/n"

  again = gets.chomp.downcase

  while again != "y" or "n"

    puts "Would you like to enter a number again? y/n"

  end

end

puts number

hold = gets


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